216=x^2/2x2x

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Solution for 216=x^2/2x2x equation: 



216=x^2/2x^2x

We move all terms to the left:

216-(x^2/2x^2x)=0



Domain of the equation: 2x^2x)!=0

x!=0/1

x!=0

x∈R



We get rid of parentheses

-x^2/2x^2x+216=0

We multiply all the terms by the denominator


-x^2+216*2x^2x=0

We add all the numbers together, and all the variables

-1x^2+216*2x^2x=0

Wy multiply elements

-1x^2+432x^2=0

We add all the numbers together, and all the variables

431x^2=0

a = 431; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·431·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{862}=0$

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